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AC to DC Rectifier
Udaipur, Rajasthan. Grant Road, Mumbai No. Sakinaka, Mumbai Unit No. Jhamarkotra Road, Udaipur Shop No. Kolkata, West Bengal. Verified Supplier Company Video. Turbhe VashiNavi Mumbai, Dist. Thane, Maharashtra. Ludhiana, Punjab. Jothipuram, Coimbatore No. Coimbatore, Tamil Nadu. Application : Electromagnetic brakes, Clutches, Clutch brake combinations, Cranes, Hoists application.
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It only takes a minute to sign up. I have many treadmills motor of rating V 10A which I would like to use for power tools. Locally we have V ac 50Hz. There are also thoughts of using PWM.
I know that high voltages probably help the motors overcome reactance quicker. But the pulsatile currents might decrease the torque. Can this be ameliorated with capacitors or inductors? Or it might run into impracticably large values required? Exactly as depicted in winny's comment. Using a drive, you will also get the benefits if an acceleration and deceleration ramp, current limiting to protect the motorand a simple variable speed control a potentiometer.
If you are just going to run the motor directly off the line, a simple bridge rectifier would work, but will probably blow up due to the inrush current to start the motor. Sign up to join this community.
The best answers are voted up and rise to the top. Home Questions Tags Users Unanswered. Ask Question. Asked 3 years, 6 months ago. Active 10 months ago. Viewed 4k times. I thought of using iron-core transformers. Another forum post points me to "single SCR in a phase-controlled half wave topology". What would be the best option?Many devices, in particular solid state electronics, must use DC or direct current.
A diode is a solid-state device that conducts in one direction only. When the anode A is positive and the cathode K is negative current flow from positive to negative will flow through the diode, through the load, and back to the power supply.Cd player plays then stops
Thus current will flow only of the positive half-cycle 0 to degrees and the diode will shut-off during the negative half-cycle from degrees to degrees. What is power? Voltage in volts is the "push" and the current in Amperes is what is being pushed. Electric charges Power is voltage times current.Benadryl and chamomile tea
Power is measured in watts. So one amp at one volt equals one watt. I'm not going into all of Ohm's Law here. See your text. We must have voltage and current together to get power, so an open switch, broken wire, or a shut-off diode delivers no power. In the case above, we get very poor power transfer with the diode off during the negative half-cycle and the positive half-cycle changing constantly between zero volts and peak.
Note that Vmax is peak. Let's say the AC in is To get peak we multiply But the average or measured voltage DC is peak times. This is what is called pulsating DC. Pure DC, such as from a 12 volt auto battery, has none of the "ripple" and will be a real 12 volts. Put a DC voltmeter across the load above in figure 1, one will read about 5. Switch the meter to AC, one will still read a voltage of some value. This is normal as one is reading the "ripple" riding the unfiltered raw D.
In figure 2 we inserted a capacitor across the load. The capacitor charges during the positive half-cycle, then discharges through the load during the negative half-cycle when we have no output. The amount of ripple is dependant on the resistance of the load and the size of the capacitor. A larger capacitor produces less ripple or a higher resistance load drawing less current thus less time for the capacitor to discharge will reduce the level of ripple because the capacitor has less time to discharge.
With no load at all, just the capacitor and the rectifier, the capacitor will charge to peak. A word of caution. If constructing these circuits observe capacitor polarity and diode polarity.
rectifier with 220V ac to 200V dc ?
Electrical Engineering Stack Exchange is a question and answer site for electronics and electrical engineering professionals, students, and enthusiasts. It only takes a minute to sign up.
A few things. First is my essential disclaimer which I use quite often on the Electronic stack exchange:. If you have to ask Stack Exchange about a high voltage device, you probably shouldn't make it. You should only rely on your own training and trusted sources. You only get one heart, and you should not put it at risk because someone on the internet said it was safe. The first thing I notice is that you are showing me a bunch of wires not enclosed in a safe plastic box.
When you plug this thing in, there's going to be V between open metal contacts. That's a terribly great safety hazard. I can only hope that you intended to correct this, and merely had the components out to make it easier to photograph them. Note that you will not generate V DC with this setup. You will generate a rectified signal which will be a half-sine-wave which peaks at V if India is anything like the US, we provide the RMS voltage on our lines, not peak.
You will then need to use other components to filter that half-sine-wave into a reasonably flat signal. Sign up to join this community. The best answers are voted up and rise to the top.
Home Questions Tags Users Unanswered. Asked 3 years ago.Gandi baat 4 episode 1
Active 3 years ago. Viewed 4k times. Can you please tell me whether it will successfully work out?
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I will attach a resistance of ohm on the DC side, as the maximum current is 3A. A picture of the circuit is attached. Wrichik Basu. Wrichik Basu Wrichik Basu 3 3 silver badges 13 13 bronze badges. First of all, I looked up this type 1N diode and it's not a Zener diode at all.
It's a rectifying diode. The fact that you think that it's a Zener diode or that a Zener diode is appropriate for this application is disturbing. Secondlythe fact that you think that it's OK to stick a ohm resistor across a volt DC bridge because the diodes can handle 3A but you don't even mention how many watts the resistor is rated for indicates that you aren't aware of all the dangers here.
Actually, did you re-edit your question? I thought that you said it was a ohm resistor, in which case you would have exceeded the power rating by a factor of almost It can kill you. If you want to learn EE, start with low voltage first.Remember Me? The current is 2 Amps. The second one is smps, its costs also comes near the transformer Any ideas please Regards Nandhu.
Regards Nandhu. You can still use the secondary for any other low power requirements. Good luck. Originally Posted by raghavendratalekar. Re: v dc drive circuit diagram. Originally Posted by nandhu Last edited by kyrietec; 28th August at Re: v to v for dc motor You don't require anything more complicated than a single SCR in a phase-controlled half wave topology.
Google the term, it can't be simpler than that. Re: v to v for dc motor I think you chaps are missing the point, its a motor, with windings, it will have inductance!! So any form of pulses or non smoothed rectified AC, will not drive 2 A at V, you will need more V. Also it will have a commutator so it will have brushes, so spark suppression is a must before the motor is connected to any semiconductor device.
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See questions and answers. Customer reviews. How does Amazon calculate star ratings? The model takes into account factors including the age of a rating, whether the ratings are from verified purchasers, and factors that establish reviewer trustworthiness.Remember Me? The current is 2 Amps. The second one is smps, its costs also comes near the transformer Any ideas please Regards Nandhu.
Regards Nandhu. You can still use the secondary for any other low power requirements. Good luck. Originally Posted by raghavendratalekar. Re: v dc drive circuit diagram. Originally Posted by nandhu Last edited by kyrietec; 28th August at Re: v to v for dc motor You don't require anything more complicated than a single SCR in a phase-controlled half wave topology. Google the term, it can't be simpler than that.
Re: v to v for dc motor I think you chaps are missing the point, its a motor, with windings, it will have inductance!! So any form of pulses or non smoothed rectified AC, will not drive 2 A at V, you will need more V. Also it will have a commutator so it will have brushes, so spark suppression is a must before the motor is connected to any semiconductor device.
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